if A =(402–2x+5), B= (3x-52 -3) and C-(6x-x+1) , find 2A-B+ 30
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Answer:
954-10x
Step-by-step explanation:
2A-B = 2(402-2x+5-(3x-52-3)
= 2(-2x -3x+402+52+5+3)
= 2(-5x+454+8)
= 2(-5x+462)
2A-B = -10x+924
2A-B+30 = -10x+924+30
2A-B+30 = -10x+954
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