Question

If A = 45 °, B = 30°, prove that : sin

cos+sin sin

= 2/3

​

Answer 1

Answer:

A=45 B=30

sinA/cosA+sinA×sinB

=sin45/cos45+sin45×sin30

1/√2/1/√2+1/√2×1/2

1/√2/1/√2+1/2√2

1/√2/2√2+√2/4

1/√2/3√2/4

1/√2×4/3√2

4/6

2/3