Question

If A=45 degrees B=30 degrees then prove that SinA/CosA+SinASinB = 2/3

Answer 1

Answer:

A=45 B=30

sinA/cosA+sinA×sinB

=sin45/cos45+sin45×sin30

1/√2/1/√2+1/√2×1/2

1/√2/1/√2+1/2√2

1/√2/2√2+√2/4

1/√2/3√2/4

1/√2×4/3√2

4/6

2/3

hope it helps

please mark me as brainliest answer

Answer 2

Answer:

answer is 1.082106781186

Step-by-step explanation:

sin45=1/√2

sin30=1/2

cos45=1/√2

cos30=√3/2

SinA/CosA+SinASinB=

(1/√2)/1+1/√2(√3/2)

1/√2+√3/2√2

1/√2+√3/√8

1/√2+3/8

1.082106781186

hope it helps you

Mark as brainliest...