If A = 45, show that sin 2A = 2sin A.cos A
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Answer:
Given :; A = 45°
LHS = Sin2A
Sin2 × 45
= Sin90°
= 1
RHS :- 2SinA CosA
2 × Sin45° × Cos45°
= 2 × 1/√2 × 1/√2
( √2 × √2 = 2 will cancel 2 )
= 1
LHS = RHS
Hence , Verified !!
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