if a= 5+2✓6 find the value of (a+a-1)
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Answer:A = 5 + 2√6
A = 3+2 + 2√(2+3) =(√3)²+(√2)² + 2√(2)×(√3)
A= {(√3)+(√2)}²
√A= √3+√2
→√A+1/√A =(A+1)/√A
=( 5 + 2√6+1)/(√3+√2)
=( 6 + 2√6)(√3-√2)/{(√3+√2)(√3-√2)}
=( 6√3 −6√ 2+2√6√3−2√6√2)/{1}
=( 6√3 −6√ 2+ 2√(2×3)√3− 2√(2×3)√2)
=( 6√3 −6√ 2+ 2×3√2− 2×2√3)
=( 6√3 −6√ 2+ 6√(2)− 4√3)
=2√3
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