If A (5, 3), B (11, -5) and P (12, y) are the vertices of a right triangle right angled at P, then y =
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y = -2, 4
Step-by-step explanation:
If A (5,3), B (11,-55) and P (12,y) are the vertices of a right angled triangle,then AB² = 10 = √(11 − 5)² + (−5 – 3)²
BC2 = = (11 – 12)² + (−5 − y)² 1 + (−5 − y)²
AB² 100 BC² = 1 + (−5 − y)²
AC² = (512)² + (3 − y)² = 49 +(3- y)²
AB² = AC² + BC²
100 = 1 + (+5+ y)² + 49 +(3- y)²
⇒ 100 = 1 + 25 + 10y + y² + 49 + 3 - 6y + y² 2y²4y
= 16
Hence, y = -2, 4
Hope it helps! :)
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