Question

If A(–5, 7), B(–4, –5), C(–1, –6) and D(4, 5) are the vertices of a quadrilateral, find the

area of the quadrilateral ABCD.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

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from the figure we get two triangles, ABD and BCD

The area of triangle ABD

= 1/2 [-5(-5-5) + (-4) (5-7) + 4(7+5) ]

= 1/2 [50+8+48]

= 106/2

= 53 sq. units

Also,

The area of triangle BCD

= 1/2 [-4(-6-5)-1(5+5) + 4(-5+6) ]

= 1/2 [44-10+4]

= 19 sq. units

Hence,, the area of the quad. ABCD

= 53 + 19

= 72 sq. units

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