Question

If A = 5 i -2 j + 3 k and B = 2i + j + 2 k then component of B along A is _____​

Answer 1

Answer:

14(2i + j + 2k)

        9

Explanation:

Component of B along A= (B. A) * vector B

                                                   B^2

B. A= 10-2+6

      = 14

Vector B= 2i + j+ 2k

Magnitude of vector B= B= root (2^ 2 + 1^2 +2^2)

                                         = root(9)

                                         = 3

Component of B along A= (B. A) * vector B

                                                   B^2

= 14 x (2i+j+2k)

        3 x 3

= 14(2i + j + 2k)

          9