Question

The maximum wavelength of of bracket series of hydrogen atom will be e​

Answer 1

Answer:

40400A

Explanation:

The maximum wavelength is formed when the transition occurs just from next orbit.

Now, for Brackett n=4

λhC​=13.6×[161​−251​]

⇒λ=13.6×0.02254.14×10−15×3×108​

⇒λ=4.05882×10−6m

⇒λ=40,588×10−10m

⇒λ=40,558A∘≈40,400A