if (a - 5y)² + (b - 6)² = 0, then find the value of (a + b -3)?
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following are the step for grtting the answer:
Given:
(a - 5y)² + (b - 6)² = 0
To find:
the value of (a + b -3)
Solution:
given that,
(a - 5y)² + (b - 6)² = 0
let,
(a - 5y)² =0 and (b - 6)² = 0
a-5y=√0 and b-6=√0
a-5y=0 and b-6=0
a=5y and b=6
we will add both the equtions
a+b=5y+6
now, we will subtract 3 from both side
we get,
a+b-3=5y+6-3
a+b-3=5y+3
hence, the value of (a + b -3) is 5y+3
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