Math, asked by vipharsh1099, 19 days ago

if (a - 5y)² + (b - 6)² = 0, then find the value of (a + b -3)?​

Answers

Answered by krishpmlak
0

Answer:

Step-by-step explanation:

Attachments:
Answered by masura8080
0

following are the step for grtting the answer:

Given:

(a - 5y)² + (b - 6)² = 0

To find:

the value of (a + b -3)

Solution:

given that,

(a - 5y)² + (b - 6)² = 0

let,

(a - 5y)² =0 and  (b - 6)² = 0

a-5y=√0     and  b-6=√0  

a-5y=0        and  b-6=0

a=5y           and   b=6

we will add both the equtions

a+b=5y+6

now, we will subtract 3 from both side

we get,

a+b-3=5y+6-3

a+b-3=5y+3

hence, the value of  (a + b -3) is 5y+3

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