If a = 6 + 2 underoot 3 , find the value of a - 1 upon a .
Answers
Answered by
0
Step-by-step explanation:
Explanation:
Given:
x
+
1
x
=
√
3
Note that:
x
+
1
x
=
2
cos
(
π
6
)
x
+
1
x
=
(
cos
(
π
6
)
+
i
sin
(
π
6
)
)
+
(
cos
(
−
π
6
)
+
i
sin
(
−
π
6
)
)
So by de Moivre's formula:
x
17
+
1
x
17
=
2
cos
(
17
π
6
)
=
2
cos
(
5
π
6
)
=
−
√
3
Answered by
0
Answer:
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Secondary School Math 5 points
If a=6+2√3 find the value of a-1/a
Ask for details Follow Report by Nikitajha400 20.06.2017
Answers
snehitha2
snehitha2
A = 6+2√3
1/a = 1/6+2√3
→ = 1/6+2√3 × 6-2√3/6-2√3
→ = (6-2√3)/(6+2√3)(6-2√3)
→ = (6-2√3)/(6²-(2√3)²)
→ = (6-2√3)/(36-4(3))
→ = (6-2√3)/(36-12)
→ = (6-2√3)/24
★a-1/a
→ 6+2√3 - (6-2√3)/24
→ {24(6+2√3) - 6 + 2√3}/24
→ {144+48√3-6+2√3}/24
→ {138+50√3}/24
→ 138/24 + 50√3/24
→ 23/4 + 25√3/12
→ {69+25√3}/12
hope it helps....mark brainly
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