Question

if a =6 - ✓35, find the value of a²+1/a²​

Answer 1

Answer:

friend I hope aap ke question ke answer mil Gaye Ho.

Step-by-step explanation:

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Answer 2

Answer:

142

Step-by-step explanation:

$a^2 = (6-\sqrt{35} )^2\\6^2-2*6*\sqrt{35} +(\sqrt{35})^2\\36-12\sqrt{35}+35\\71-12\sqrt{35}\\\\\frac{1}{a} =\frac{1}{6-\sqrt{35} } *\frac{6+\sqrt{35}}{6+\sqrt{35}} \\\frac{6+\sqrt{35}}{6^2-\sqrt{35}^2} \\\frac{6+\sqrt{35}}{36-35} \\6+\sqrt{35}\\\\\frac{1}{a^2}= (6+\sqrt{35})^2\\6^2+2*6*\sqrt{35}+\sqrt{35}^2\\36+12\sqrt{35}+35\\=71+12\sqrt{35}\\\\a^2+\frac{1}{a^2} = 71-12\sqrt{35}+71+12\sqrt{35}\\71+71 = 142$

please make me brainlist....