If A=60°,then prove cos2A=cos²A-sin²A
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Answered by
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Step-by-step explanation:
L.H.S=sin2A=sin2×60
∘
=sin120
∘
=sin(180
∘
−60
∘
)=sin60
∘
=
2
3
..(1)
R.H.S=2sinAcosA=2sin60
∘
cos60
∘
=2×
2
3
×
2
1
=
2
3
..(2)
From (1) and (2) we have
L.H.S=R.H.S
Hence verified.
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