If a = 7-4√3, Find the value of √a +1/√a
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Given that :
=> a = 7- 4√3
=> ( a - 7 ) = -4√3
#squaring both sides
=> (a-7)² = (-4√3)²
=> a² + 49 -14a = 48
=> a² -14a +1 = 0
=> a² + 1 = 14a
=> (a²+1)/a = 14 --------(1)
Now we have to find the value of :
=> √a + 1/√a = X (let)
#squaring both sides
=> (√a+1/√a) = X²
=> a + 1/a + 2 = X²
=>( a²+1)/a + 2 = X²
put the value of (a²+1)/a from equation (1) :
=> 14+2 = X²
=> X² = 16
=> X = ±√16 = 4
so X = (√a +1/√a ) = 4 ans.
______________________________
⭐Hope it will help you:D
Given that :
=> a = 7- 4√3
=> ( a - 7 ) = -4√3
#squaring both sides
=> (a-7)² = (-4√3)²
=> a² + 49 -14a = 48
=> a² -14a +1 = 0
=> a² + 1 = 14a
=> (a²+1)/a = 14 --------(1)
Now we have to find the value of :
=> √a + 1/√a = X (let)
#squaring both sides
=> (√a+1/√a) = X²
=> a + 1/a + 2 = X²
=>( a²+1)/a + 2 = X²
put the value of (a²+1)/a from equation (1) :
=> 14+2 = X²
=> X² = 16
=> X = ±√16 = 4
so X = (√a +1/√a ) = 4 ans.
______________________________
⭐Hope it will help you:D
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