if a 8 BC is exactly divisible by 1287 find the value of each of the digit A B and C
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The number A8BC should be completely divisible by 1287
if we multiply 1287 by 3 we get 3861 and on 100s place we have 8 in the original number and in 3861 so we can say this is the number
and the values are A = 3
B = 6
C = 1
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The above answer so why should I write it again
I am just tell ing you that the above answer is right
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