If a= 9-4root5. Find the alue of a square + 1by a square
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a=9-4√5.
We need to find the value of (a²+1)/a²
For this firstly we will find the value of a².
Since a=9-4√5; hence a²=(9-4√5)²
Applying the formule (a+b)²=a²+b²+2ab, we get
(9-4√5)²
= 9²+(4√5)²-2.9.(4√5)
=81+80-72√5
=161-72√5
=161-72(2.23)
=0.44
Now that we have the value of a²=0.44, we can easily get the value of (a²+1)/a² which is shown below
(a²+1)/a² = (0.44+1) / 0.44
= 1.44/0.44
= 3.27
We need to find the value of (a²+1)/a²
For this firstly we will find the value of a².
Since a=9-4√5; hence a²=(9-4√5)²
Applying the formule (a+b)²=a²+b²+2ab, we get
(9-4√5)²
= 9²+(4√5)²-2.9.(4√5)
=81+80-72√5
=161-72√5
=161-72(2.23)
=0.44
Now that we have the value of a²=0.44, we can easily get the value of (a²+1)/a² which is shown below
(a²+1)/a² = (0.44+1) / 0.44
= 1.44/0.44
= 3.27
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