if A=90 B=6x-5,c=7x-15 ,D=2x+6 find x and angle b,c
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To find :
we need to find the value of x and angle b and c.
Solution :
- A = 90°
- B = 6x - 5
- C = 7x - 15
- D = 2x + 6
‹‹ Sum of all angles of quadrilateral = 360° ››
→ A + B + C + D = 360
→ 90 + (6x - 5) + (7x - 15) + (2x + 6) = 360
→ 6x + 7x + 2x - 5 - 15 + 6 + 90 = 360
→ 15x - 20 + 96 = 360
→ 15x + 76 = 360
→ 15x = 360 - 76
→ 15x = 284
→ x = 284/15
- → x = 18.9
So,
- Angle B
6x - 5
= 6 × 18 .9 - 5
= 113.4 - 5
= 108 .4
- Angle C
7x - 15
= 7 × 18.9 - 15
= 132.3 - 15
= 117.3
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