Question

If a (a-2) and 3a are in ap find the value of a

Answer 1

hope it will be helpful to you

Answer 2

Answer:

$\green {Value \: of \: a = -2}$

Step-by-step explanation:

$\red { Given \: a,\:(a-2),\: and \: 3a \: are \:in \:A.P}$

$\pink { Difference \: of \: two \: consecutive \\terms \: are \: equal \:in\:A.P}$

$\blue { a_{2} - a_{1} = a_{3} - a_{2} }$

$\implies (a-2) - a = 3a - (a-2)$

$\implies a - 2 - a = 3a - a + 2$

$\implies -2 = 2a + 2$

$\implies -2 - 2 = 2a$

$\implies -4 = 2a$

$\implies \frac{-4}{2} = a$

$\green { -2 = a }$

Therefore.,

$\green {Value \: of \: a = -2}$

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