If A(a,5) B(-1,-6) C(-4,b) are the three vertices of triangle ABC and centroid is (-1/3,2) Then find (a+b),
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Answered by
0
Answer:
a=4
b=7
Step-by-step explanation:
G1= A1+B1+C1/3
-1/3=a-1-4/3
-3=3(a-5)
-3=3a-15
3a = 15-3
3a= 12
a=4
Now, G2= A2+B2+C2
2 = 5-6+b/3
2×3= -1+b
6= -1+b
b= 6+1
b=7
Answered by
0
Answer:
Step-by-step explanation:
X CORDINATES=
x1=a
x2=-1
x3=-4
Y CORDINATE=
y1=5
y2=-6
y3=b
Xcordinate of cntroid=x1+x2+x3/3
-1/3=a-1-4/3
a=4
Ycordinate of centroid=y1+y2+y3/3
2=5-6+b/3
b=7
a+b=4+7
=11
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