Math, asked by sanKUDADA, 1 year ago

IF A+A+A+A+A+A+A+A+A+A+A=2546509922 FIND THE VALUE OF 3A?

Answers

Answered by vasanta
9
Value of A=2546509922÷11 =231500902 Value of 3A= 231500902×3 =694502706

vasanta: Hope it helps umark it as the best..plz
vasanta: Iam dividing it by 11 becoz thr r 11 A's in the question
Answered by hifza
1
11A = 2546509922
A   = 2546509922 ÷ 11 =231500902
THUS,
         3A = 231500902 × 3
             =694502706 ANS

hifza: plzz mark s best
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