If a/a+b=b/c+a=c/a+b and a+b+c≠0,then the value of each ratio is?
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a/(b+c)=b/(c+a)=c/(a+b)=ka/(b+c)=b/(c+a)=c/(a+b)=k
a=k(b+c)a=k(b+c)
b=k(c+a)b=k(c+a)
c=k(a+b)c=k(a+b)
by property sum of numerator/sum of denominator is also = k
a+b+c/2(a+b+c)=ka+b+c/2(a+b+c)=k
k=1/2k=1/2
If a+b+c=0a+b+c=0
a+b=−corb+c=−aa+b=−corb+c=−a
a/b+c=a/−a=−1=ka/b+c=a/−a=−1=k
So k=−1or1/2
a=k(b+c)a=k(b+c)
b=k(c+a)b=k(c+a)
c=k(a+b)c=k(a+b)
by property sum of numerator/sum of denominator is also = k
a+b+c/2(a+b+c)=ka+b+c/2(a+b+c)=k
k=1/2k=1/2
If a+b+c=0a+b+c=0
a+b=−corb+c=−aa+b=−corb+c=−a
a/b+c=a/−a=−1=ka/b+c=a/−a=−1=k
So k=−1or1/2
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