Question

If -a-√a2- 4bc ÷then find bx2+ ax=​

Answer 1

Step-by-step explanation:

ANSWER

Roots of quadratic equation when it is equal

b

2

−4ac=0

Given in the equation

(b−c)x

2

+(c−a)x+(a−b)=0

Here if we put the values insides the quadratic equation b

2

−4ac:−

b=(c−a)

a=(b−c)

c=(a−b)

Discriminant D=b

2

−4ac=0

⇒(c−a)

2

4(a−b)(b−c)=0

⇒(c

2

+a

2

−2ac)−4(ab−b

2

−ac+bc)=0

⇒c

2

+a

2

−2ac−4ab+4b

2

+4ac−4bc=0

⇒a

2

+4b

2

+c

2

−4ab−4bc+2ac=0

⇒(a−2b+c)

2

=0

⇒a−2b+c=0

⇒a+c=2b

⇒(b−a)=(c−b) [We can write the expression

a+c=2baas(b−a)=(c−b)

So the required condition for a,b,c therefore

a,b,c are in A.P [Proved