Question

If A ABC is an isosceles triangle such that AB = AC,
then prove that altitude AD from A on BC bisects BC.​

Answer 1

Answer:

Hey mate ,here is ur answer

Step-by-step explanation:

We have to show that

∠BAD=∠CAD and BD = DC.

In right triangles ADB and ADC, we have

AB = AC (given);

AD = AD (common side).

So by RHS congruency of triangles, we have △ABD≅△ACD. Hence, ∠BAD=∠CAD and BD=DC.

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