Math, asked by seemajoshy076, 9 months ago

If a∆ABC is right angled at C ,then find the value of sec(A+B) is....?
a) 0
b)1
c)2/✓3
d) not defined

Answers

Answered by nalinikes
0

Answer:

Step-by-step explanation:

Not defined

Answered by agnihotriabhay40
3

Answer:

this is the answer

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Step-by-step explanation:

triangle is right-angled on c

so, angleA+angleB+angleC=180(sum of angles of triangle)

A+B+90=180(C is 90°)

A+B=90°

so, sec(A+B)

=sec(90°)

=not defined

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