Math, asked by mona3794, 1 year ago

If a age is 10% greater than b then b age is how muh less than a

Answers

Answered by shubham7426
0
b+b of10%=b+b×10/100=b+b/10=11b/10
Answered by Anonymous
0

Let B's age be x years.

A's age = x × 110/100 = 11x /10

B is less than A = 11x/10 - x = x/10

less% = x/10×10/11x ×100% = 100/11% = 9  1/11 %

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