If a age is 10% greater than b then b age is how muh less than a
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b+b of10%=b+b×10/100=b+b/10=11b/10
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Let B's age be x years.
A's age = x × 110/100 = 11x /10
B is less than A = 11x/10 - x = x/10
less% = x/10×10/11x ×100% = 100/11% = 9 1/11 %
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