if a anb B are zero's of quadratic polynomial p(x) = x²- 8x + k ,such that a-B = 4 ,then value of k is
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Answer:
Given:−
p(x) = x² - 8x + k
α² + β² = 40
\large\bf\underline {To \: find:-}Tofind:−
Value of k.
\huge\bf\underline{Solution:-}Solution:−
it is given that α and β are the zeroes of the given polynomial.
»»p(x) = x² - 8x + k
a = 1
b = -8
c = k
≫ Sum of zeroes = - b/a
⠀⠀⠀⠀⠀»» α + β = -(-8)/1
⠀⠀⠀⠀⠀»» α + β = 8
≫ product of zeroes = c/a
⠀⠀⠀⠀⠀»» αβ = k
we know that,
★ (a + b) ² = a² + b² + 2ab
≫ (a + b)² - 2ab = a² + b²
So,
⠀⠀⠀⠀⠀»» (α + β)² - 2ab = a² + b²
⠀⠀⠀⠀⠀»» 8² -2× k = 40
⠀⠀⠀⠀⠀»» 64 - 2k = 40
⠀⠀⠀⠀⠀»» - 2k = 40 - 64
⠀⠀⠀⠀⠀»» - 2k = -24
⠀⠀⠀⠀⠀»» k = -24/-2
⠀⠀⠀⠀⠀»» k = 12
✦ Value of k is 12.
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