Question

If A and (2A – 45°) are acute angles such that sin A = cos (2A – 45°), then tan A is equal to
1 point
0
(b) 1/√3
(c) 1
(d) √3​

Answer 1

• Solution :-

• A and (2A - 45°) are acute angle

now ,.

• = > sin A = cos (2A – 45°)
• => sinA = Sin { 90° - ( 2A – 45°) }
• => sinA = Sin { 90° - 2A + 45° }
• => sinA = Sin { 135 ° - 2A }

so , A = 135 ° - 2A

• => 3 A = 135 °
• => A = 45°