Math, asked by MeghanaNM, 5 hours ago

If (x-1) is one the factor of x²+px-3, then the value of p in x²+px-3-0 is.​

Answers

Answered by siranjivicars
5

Step-by-step explanation:

g(x) = x-1

x-1=0

x=1

p(1)=1^2+p(1)-3

= 1+p-3

-p = -2

p =2

Answered by soumyasangeeta12
4

Answer:

Hope this will help you for exams

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