Question

If (x-1) is one the factor of x²+px-3, then the value of p in x²+px-3-0 is.​

Answer 1

Step-by-step explanation:

g(x) = x-1

x-1=0

x=1

p(1)=1^2+p(1)-3

= 1+p-3

-p = -2

p =2

Answer 2

Answer:

Hope this will help you for exams