Question

If a and ß are the zeroes of the quadratic polynomials given below
1. p(x) = 6x^2 +x-2​

Answer 1

Answer:

6X²+X-2=0

Step-by-step explanation:

X=(-b±√b²-4ac)/2a

a=6,b=2&c=-2

→X=[-2±√4+48]/2(6)

→X=[-2±√52]/12

→X=([-2+√52]/12)&([-2-√52])12

→Zeros of p(x) are

(-2+√52)/12  &  (-2-√52)/12