Math, asked by prachisingh1602, 2 months ago

If a and ß are the zeros of p(x)= x^2-5x
+ 6. then value of a+ß-3aß is
-23
-13
8
13
23​

Answers

Answered by harshita220804
2

Answer:

-13

Step-by-step explanation:

x^2-5x+6 is given

alpha and beta are the zeroes

so alpha+beta=-b/a=5

alpha*beta=c/a=6

so put these values in the ques

a+ß-3aß=-13

Similar questions