if a and ß are the zeros of polynomials 2x²-3+4,find a²+ß²
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Answer:
alpha + beta = -b/a = 3/2
alpha(beta) = c/a = 4/2 = 2
(alpha + beta)^2 = (alpha)^2 +(beta)^2 +2(alpha(beta))
(alpha)^2 + (beta)^2 = 9/4 - 4 = 9 - 16/4
(alpha)^2 + (beta)^2 = -7/4
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