Question

If a and ß are the zeros of the polynomial f(X)=x²-6x+k. Find the value of k such that a² + ß²=40

A)-2
B)4
C)5
D)6
give solution step by step...​

Answer 1

Answer:

k = -2

Step-by-step explanation:

${x}^{2} - 6x + k$

$\alpha + \beta = 6$

$\alpha \beta = k$

${( \alpha + \beta )}^{2} = { \alpha }^{2} + { \beta }^{2} + 2 \alpha \beta$

$36 = 40 + 2k$

$k = - 2$

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