Math, asked by dilipkumar9431555707, 6 months ago

If a and ß are zeroes of x² - 6x + 6 then the
value of a ² +beta
squre is​

Answers

Answered by Anonymous
42

If alpha and beta are the zeroes of the quadratic polynomial x^2-x-6, then how would you find the value of alpha^4+beta^4?

Now, if you know [Math Processing Error] and [Math Processing Error], it is very easy to determine the value of the expression [Math Processing Error]. So, how do you find [Math Processing Error] and [Math Processing Error]? Well, you could try looking for simple factors of the quadratic, or you could use the formula for calculating the roots of a quadratic equation or you could form the square. In this particular case, all three methods are very simple.

However, there is a method that you can use for your calculation that doesn’t involving finding [Math Processing Error] and [Math Processing Error]! In this case, it is the more complex way; however, sometimes, it can be quicker.

The trick is to make use of the fact that for the quadratic [Math Processing Error],

[Math Processing Error]

[Math Processing Error]

[If [Math Processing Error] and [Math Processing Error] are the roots of the quadratic, then [Math Processing Error].

Multiplying this out, we have [Math Processing Error]

Equating the coefficients of this quadratic with the initial quadratic, we have:

[Math Processing Error] Equation 1.

[Math Processing Error] Equation 2.]

In our quadratic, [Math Processing Error], [Math Processing Error] and [Math Processing Error], so we have:

[Math Processing Error]

[Math Processing Error]

Now, how does this help us?

Well, [Math Processing Error]

[Math Processing Error]

[Math Processing Error]

[Math Processing Error]

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