If A and B are (-2,-2) and (2,-4) respectively
find the co-ordinates of 'P' such that
AP = 3 AB and 'p' lies on the segment
AB
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Step-by-step explanation:
Given If A and B are (-2,-2) and (2,-4) respectively find the co-ordinates of 'P' such that AP = 3 AB and 'p' lies on the segment AB
- AP = 3 AB and 'p' lies on the segment
- AB
- Let the co-ordinates of point P be P(x,y)
- Given AP = 3 (AB)
- So AP = 3(AP + PB)
- A.P = 3 AP + 3 PB
- -2 AP = 3 PB
- AP / PB = - 3 / 2
- Therefore point P divides AB in the ratio of – 3 : 2
- Using section formula we get
- So m1 = - 3, m2 = 2, x1 = -2, x2 = 2, y1 = - 2, y2 = - 4
- So X = m1 x 2 + m2 x1 / m1 + m2
- = - 3 x 2 + 2 x – 2 / - 3 + 2
- = - 6 – 4 / - 1
- = - 10 / - 1
- = 10
- Now Y = m1y2 + m2y1 / m1 + m2
- = - 3 x – 4 + 2 x – 2 / - 3 + 2
- = 12 – 4 / - 1
- = - 8
Therefore coordinates of P are p (x,y) = p (10, - 8)
Reference link will be
https://brainly.in/question/2676660
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