Question

If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠ A = ∠ B.
Please give the answers clear..Let the answers be from u​

Answer 1

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$\large \tt \red{✦Answer✦}$

In triangle ABC ,

Cos A = opposite side / hypo.

= AC / AB -1

Cos B = adjacent side / hypo.

= BC / AB -2

We gave cos A = cos B

Thus by 1 and 2,

AC / AB = BC / AB

Thus

AC . AB = BC . AB

AC = BC

thus AC and BC are two sides of triangle ABC

Thus angle A = angle B

( angles opposite to equal sides are equal )

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