If a and b are natural numbers satisfying a3 – b3 = ab + 61, then find the value of a + b.
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Step-by-step explanation:
a^3 - b^3 = ( a-b) ( a^2 + ab + b^2) = ab + 61
(a-b )^3 = a^3 - b^3 - 3ab(a-b) = ab + 61
putting value for a^3 - b^3
= ab + 61 - 3ab ( a-b)
-2ab + 61 = a-b
a = 5 , b=6
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