Question

If A and B are points (-6,7) and (-1,-5) respectively then find the distance of 2AB

Answer 1

AB=√(-1-(-6))^2+(-5-7)^2
AB=√(5)^2+(-12)^2
AB=√25+144
AB=√169
hence AB=13
therefore 2AB=2×13
2AB=26

Answer 2

Answer:

$Distance \:of \:2AB=26\:units$

Step-by-step explanation:

$Given \:two\:points \:A(-6,7)\\and\:B(-1,-5).$

$By\:using\: distance\: formula:\\\boxed {d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}}$

$Here, \\x_{1}=-6,\:y_{1}=7;\\x_{2}=-1,\:y_{2}=-5;$

$\implies Distance (AB)\\=\sqrt{[-1-(-6)]^{2}+(-5-7)^{2}}\\=\sqrt{(-1+6)^{2}+(-12)^{2}}\\=\sqrt{5^{2}+(-12)^{2}}\\=\sqrt{25+144}\\=\sqrt{169}\\=\sqrt{13^{2}}\\=13$

$\implies 2AB\\= 2\times 13\\=26 \:units$

Therefore,

$Distance \:of \:2AB=26\:units$

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