Question

if a and b are positive integers such that 100/151<a/b<200/251. find least possible value of (a+b). ​

Answer 1

Solution :-

(100/151) can be written as ,

→ (100/151) * (2/2) = (200/302)

So,

→ (200/302) < a/b < (200/251)

we know that,

• a/m < a/n when m > n .
• Example :- 6/3 = 2 and 6/2 = 3 , So, 6/3 < 6/2 and 3 > 2 .

then,

→ (200/302) < (200/301) < (200/300) < (200/299) < _______________ < (200/251)

as, we can see that, one rational number between (200/302) and (200/251) is (200/300) .

therefore,

→ 200/300 = 2/3

hence,

→ a/b = 2/3

→ (a + b) = 5 (Ans.)

∴ Least possible value of (a+b) is equal to 5 .

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