Question

If a and b are positive real numbers,then which of the following is not true?(a)√ab=√a√b(b)(a+b)(a-b)=2a (c)(√a+√b)(√a-√b)=a-b(d)√ab=(ab)1/X




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Answer 1

Answer:

If a and b are positive real numbers,then which of the following is not true?(a)√ab=√a√b(b)(a+b)(a-b)=2a (c)(√a+√b)(√a-√b)=a-b(d)√ab=(ab)1/X

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Answer 2

Answer:

It's (b) (a+b)(a-b) = 2a

Step-by-step explanation:

It's known that if a and b are positive real numbers then (a+b) (a-b) = a^2 - b^2

$(a + b)(a - b) = {a}^{2} - ab + ab - {b }^{2} \\ = {a}^{2} - {b}^{2}$

That's why (b) (a+b)(a-b) = 2a is not true.