If a and b are rational numb
ers find the value of a and b in each of the following equation root 3 + root 2 by root 3 minus root 2 is equals to a + b root 6
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Answer:
a=5 b=2
Step-by-step explanation:
(root 3 + root 2)/(root 3 - root 2) multiply numerator and denominator with (root 3 + root 2)
(root 3 + root 2)/(root 3 - root 2)
=((root 3 + root 2) * (root 3 + root 2)) / ((root 3 - root 2) *(root 3 + root 2))
=(root 3 + root 2)^2 /((root 3)^2 - (root 2)^2)
=( (root 3)^2 +(root 2)^2 + 2 * root 3* root 2 ) / (3-2)
=(3 + 2 + 2 *root 6) /1 here root 3* root 2=root (3*2)=root 6
=5 + 2 *root 6 = a + b root 6
comparing these two we get a=5 b = 2
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