If a and b are rational numbers and 3√2+2√3÷5√2-4√3=a-b√6. Find value of a and b
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rationalize and compare with a-b√6
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3√2+2√³÷5√²-4√³=a-b√6
3√²+2√³÷5√²-4√³×5√2+4√³÷5√²+4√³ [rationalising]
30+12√6+10√6+24÷50-48
54+22√6÷2
2[27+11√6]÷2
27+11√6
a=27 b=11
3√²+2√³÷5√²-4√³×5√2+4√³÷5√²+4√³ [rationalising]
30+12√6+10√6+24÷50-48
54+22√6÷2
2[27+11√6]÷2
27+11√6
a=27 b=11
saklani2003:
thanks
no problem!:)
b will be -11
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