Question

If a and b are real , prove that (a+b)²=4ab sin²a is possible only when a=b​

Answer 1

Step-by-step explanation:

We know the algebraic identities:

1) (x+y)² = x²+2xy+y²

2)(x-y)² = x²-2xy+y²

Now,

RHS = (a+b)²-4ab

= a²+2ab+b²-4ab

= a²-2ab+b²

= (a-b)²

= LHS

Therefore,

(a-b)²=(a+b)²-4ab

I hope it will help you..