Math, asked by karthi56, 4 months ago

if a and b are roots of equation x^2+x-7=0 then find a^3+b^3​

Answers

Answered by JashanR
2

Answer:

A=

x

2

7

3

x

6

7

2

x

Det(A)=x(x

2

−12)−3(2x−14)+7(12−7x)

⇒0=x

3

−12x−6x+42+84−49x

0=x

3

−67x+126

Since the sum of roots is the coefficient of x

2

, which is zero here,

Let a be the third root.

So, a+2+7=0

the third root would be −9.

Step-by-step explanation:

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Answered by Yashsoni703
4

Step-by-step explanation:

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