if a and b are roots of equation x^2+x-7=0 then find a^3+b^3
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2
Answer:
A=
⎣
⎢
⎢
⎡
x
2
7
3
x
6
7
2
x
⎦
⎥
⎥
⎤
Det(A)=x(x
2
−12)−3(2x−14)+7(12−7x)
⇒0=x
3
−12x−6x+42+84−49x
0=x
3
−67x+126
Since the sum of roots is the coefficient of x
2
, which is zero here,
Let a be the third root.
So, a+2+7=0
the third root would be −9.
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