If A and B are sets and AUB=AnB,then:
a. A={ }
b. B={ }
c. A=B
d. none of these
Answers
c. A=B
as the intersection{common part} and union{addition of both the parts} are equal
I'll quote proof it must HELP
Let A = B
AUB = A
A intersection B = A implies A U B = A intersection B
A = B implies AU B = intersection B ---- (1)
Now let A U B = A intersection B. Then we have to prove that A = B. For this let x belongs to A implies x belongs to A U B
= x belongs to A intersection B
= x belongs to A and x Belongs to B
= x belongs to B
so A subset of B --- (2)
Now we will let y belong to B which implies y belongs to A U B
= y belongs to A intersection B
= y belongs to A and y belongs to B
= y belongs to A
Therefore, B subset of A --- (3)
from (2) and (3) we get A=B
so A union B will be equal to A intersection B implies A = B ---(4)
From (1) and (4) we will get
A union B = A INTERSECTION B Implies A = B
MARK BRAINLIEST
SOLUTION
TO CHOOSE THE CORRECT OPTION
If A and B are sets and A ∪ B = A ∩ B then
a. A = { }
b. B = { }
c. A = B
d. None of these
EVALUATION
Here it is given that A and B are sets and A ∪ B = A ∩ B
Now we show that A ∪ B = A ∩ B implies A = B
Let x ∈ A
⇒ x ∈ A ∪ B
⇒ x ∈ A ∩ B
⇒ x ∈ B
∴ A ⊆ B - - - - - (1)
Next let x ∈ B
⇒ x ∈ A ∪ B
⇒ x ∈ A ∩ B
⇒ x ∈ A
∴ B ⊆ A - - - - - (2)
From Equation 1 and Equation 2 we get
A = B
FINAL ANSWER
Hence the correct option is c. A = B
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