Question

if a and b are the roots of equation x^2-6x+6=0 then the value of a^2+b^2​

Answer 1

Answer:

24

Step-by-step explanation:

by factorizing we get roots a and b as

a = 3+√3 , b = 3-√3

a^2 + b^2 = (3+√3)^2 + (3-√3)^2

a^2 + b^2 = (3)^2 + (√3)^2 + 2(3)(√3) + (3)^2 + (√3)^2 - 2(3)(√3)

a^2 + b^2 = 9 + 3 + 9 + 3

a^2 + b^2 = 24

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a^2 + b^2 = 24