Question

if a and B are the zeroes of a polynomial x^2-6x+k such that a^2+B^=40
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Answer 1

In polynomial x² - 6x + k we have,

→ a + b = 6

Given : a² + b² = 40

→ (a + b)² = a² + b² + 2ab

→ 36 = 40 + 2ab

→ - 4/2 = ab

→ ab = - 2

Since ab = k therefore,

k = - 2

Hence value of k is - 2.

Answer 2

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