If a and b are the zeroes of polynomial x²+kx+45 such that (a+b)²=144, find the value of k
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Hey
Here is your answer,
x²+kx+45 =0
Sum of zeroes = -b/a
a + b=-k/1
=-k
It is given that ,
(a+b)^2 = 144
a+b =√144
a+b =12
-k=12
k = -12
Hope it helps you!
Here is your answer,
x²+kx+45 =0
Sum of zeroes = -b/a
a + b=-k/1
=-k
It is given that ,
(a+b)^2 = 144
a+b =√144
a+b =12
-k=12
k = -12
Hope it helps you!
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