Question

If a and b are the zeroes of the polynomial 6x^2+x-1.(1) findthe value ofb/a+a/b+2(1/a+1/b)+2.(2) find the polynomial whose zeroes are:a^2b and b^2a.​

Answer 1

Answer:

HII MATE

HERE'S THE ANSWER

Step-by-step explanation:

Let’s first solve the equation to get our zeroes of the equation i.e. alpha and beta.

6x2+x−2=0

6x2+4x−3x−2=0

2x(3x+2)−(3x+2)=0

which gives us two equations,

2x−1=0=>x=1/2(alpha)

3x+2=0=>x=−2/3(beta)

So, the value of alpha/beta and beta/alpha will be -3/4 and -4/3, adding both of them gives the solution as -25/12.

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