If a and b are the zeroes of the polynomial 6x^2+x-1.(1) findthe value ofb/a+a/b+2(1/a+1/b)+2.(2) find the polynomial whose zeroes are:a^2b and b^2a.
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Step-by-step explanation:
Let’s first solve the equation to get our zeroes of the equation i.e. alpha and beta.
6x2+x−2=0
6x2+4x−3x−2=0
2x(3x+2)−(3x+2)=0
which gives us two equations,
2x−1=0=>x=1/2(alpha)
3x+2=0=>x=−2/3(beta)
So, the value of alpha/beta and beta/alpha will be -3/4 and -4/3, adding both of them gives the solution as -25/12.
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