If a and B are the zeroes of the polynomialp(x) = 2x^2 + 11x + 5, find the values of :
(i) a^2 +b^2
(ii)1/a+1/b-2ab
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Sum of zeroes = a+ b= -b / a =-11/2
Product of zeroes = ab = c/a = 5/2
i/) a^2 + b^2
= (a+b)^2 - 2ab
=(-11/2)^2 - 2*5/2
=121/4-10/2
= 121/4-20/4
= 101/4
Mark me and get the second part
JobanJosan123:
thank you very much
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