Math, asked by JobanJosan123, 10 months ago

If a and B are the zeroes of the polynomialp(x) = 2x^2 + 11x + 5, find the values of :
(i) a^2 +b^2
(ii)1/a+1/b-2ab​

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Answered by Anonymous
1

Sum of zeroes = a+ b= -b / a =-11/2

Product of zeroes = ab = c/a = 5/2

i/) a^2 + b^2

= (a+b)^2 - 2ab

=(-11/2)^2 - 2*5/2

=121/4-10/2

= 121/4-20/4

= 101/4

Mark me and get the second part


JobanJosan123: thank you very much
JobanJosan123: I can't mark because only you have answered this question
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