Math, asked by shafaq37, 3 months ago

If a and B are the zeroes of the quadratic polynomial f(x) = 6x^2+ x - 2, then the value
of 1.a^2+b^2. 2.1/a+1/b

Answers

Answered by Anonymous
4

Step-by-step explanation:

f(x)=6x

2

+x−2

a,b are its zero's / roots.

a+b=

6

−1

,ab=

6

−2

=−1/3

b

a

+

a

b

=

ab

a

2

+b

2

=

ab

(a+b)

2

−2ab

=

(−1/3)

(−1/6)

2

−2(−1/3)

=

−1/3

36

1

+

3

2

=−(

12

1

+2)=

12

−25

Answered by Anonymous
2

Answer:

good noon

purple u

i hope u r fine XD

_____________________

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